Feds: Ga. illegal immigrant population 6th largest
Mar 24, 2012 | 577 views | 2 2 comments | 2 2 recommendations | email to a friend | print
Pro immigration Demonstrators march outside the 11th U.S. Circuit Court of Appeals which is hearing arguments in the legal challenges against tough new laws targeting illegal immigration in Alabama and Georgia, Thursday, March 1, 2012, in Atlanta. (AP Photo/John Amis)
Pro immigration Demonstrators march outside the 11th U.S. Circuit Court of Appeals which is hearing arguments in the legal challenges against tough new laws targeting illegal immigration in Alabama and Georgia, Thursday, March 1, 2012, in Atlanta. (AP Photo/John Amis)
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ATLANTA (AP) — A federal report shows Georgia had the sixth-largest number of illegal immigrants in the country in January 2011, months before lawmakers passed a tough law targeting illegal immigration.

The Department of Homeland Security report released Friday shows that about 440,000 illegal immigrants lived in Georgia. Only California, Texas, Florida, New York and Illinois had larger illegal immigrant populations.

DHS estimates that the total number of illegal immigrants in the country in January 2011 was 11.5 million, roughly the same as the year before.

Estimates from a year earlier, in January 2010, put the number of illegal immigrants in Georgia at 460,000. But DHS cautioned against comparing the January 2011 numbers with estimates from previous years because of changes in the method used to calculate the illegal immigrant population.
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Istillwantequalrights
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March 24, 2012
A more important calculation might be the effect that would be made if we brought our troops back into this country and put them on our borders.
Shoesandshoes
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March 24, 2012
How is this calculated?
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